A clinical trial is being conducted in order to determine the efficacy of a new drug used to treat Rheumatoid arthritis. The efficacy of the medication will not only be determined by the physical improvement of symptoms but also by using a blood test to examine the concentration C-reactive protein (an inflammatory marker) in an individual’s blood. If the researcher wants a margin of error for the level of C-reactive protein to be less than or equal to 3.0 mg/dL, and if the standard deviation for C-reactive protein concentrations among arthritis patients was previously documented at 8 mg/dL, how many patients should be recruited for each group in the study assuming a 95% confidence interval will be used to quantify the mean differences between the control group and the treatment group?     n for the treatment group = 112; n for the control group = 111     n for the treatment group = 56; n for the control group = 57     n for the treatment group = 55; n for the control group = 55     n for the treatment group = 112; n for the control group = 112

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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A clinical trial is being conducted in order to determine the efficacy of a new drug used to treat Rheumatoid arthritis. The efficacy of the medication will not only be determined by the physical improvement of symptoms but also by using a blood test to examine the concentration C-reactive protein (an inflammatory marker) in an individual’s blood. If the researcher wants a margin of error for the level of C-reactive protein to be less than or equal to 3.0 mg/dL, and if the standard deviation for C-reactive protein concentrations among arthritis patients was previously documented at 8 mg/dL, how many patients should be recruited for each group in the study assuming a 95% confidence interval will be used to quantify the mean differences between the control group and the treatment group?

   

n
for the treatment group = 112; n for the control group = 111

   

n
for the treatment group = 56; n for the control group = 57

   

n
for the treatment group = 55; n for the control group = 55

   

n
for the treatment group = 112; n for the control group = 112
 

Expert Solution
Step 1

It is given that both standard deviations, σ1 = σ2 = 8.

Margin of error, E = 3.0

The z-critical value for 95% confidence interval is 1.96.

Assume the sample sizes are equal for both control and treatment groups.

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