A closed system contains an ideal gas, which molecular weight is W = 63.47 kg/kmol, and its standard state entropy is S0 = 0. The system undergoes the following cycle: at state 1 the temperature is 295.15 K, the pressure is 95 kPa (absolute), and the entropy is 46.450 J/(kg/kmol). The gas is compressed polytropically at n = 1.46 until the specific volume is 10 times lower than that at state 1 ( state 2 ). Then 85651.7 J/kg of heat is added at constant specific volume ( state 3). After that heat is added at constant pressure until entropy is 333.333 J/(kg.K) (state 4). In the next process the system undergoes isentropic expansion (and reaches state 5 ). Finally there is a constant volume rejection of heat (until state 1). Determine a) the values of p, v, T and s, at each cycle point; b) the p-V and T-s diagrams of cycle; c) the heat added to the system; d) the heat rejected by the system; e) the cycle net work; f) the mean effective pressure; g) the cycle thermal efficiency.
A closed system contains an ideal gas, which molecular weight is W = 63.47 kg/kmol, and its standard state entropy is S0 = 0. The system undergoes the following cycle: at state 1 the temperature is 295.15 K, the pressure is 95 kPa (absolute), and the entropy is 46.450 J/(kg/kmol). The gas is compressed polytropically at n = 1.46 until the specific volume is 10 times lower than that at state 1 ( state 2 ). Then 85651.7 J/kg of heat is added at constant specific volume ( state 3). After that heat is added at constant pressure until entropy is 333.333 J/(kg.K) (state 4). In the next process the system undergoes isentropic expansion (and reaches state 5 ). Finally there is a constant volume rejection of heat (until state 1). Determine a) the values of p, v, T and s, at each cycle point; b) the p-V and T-s diagrams of cycle; c) the heat added to the system; d) the heat rejected by the system; e) the cycle net work; f) the mean effective pressure; g) the cycle thermal efficiency.
Step by step
Solved in 11 steps with 23 images
