A coil 4.20 cm radius, containing 420 turns, is placed in a uniform magnetic field that varies with time according to B=(1.20×10 2T/s)+( 2.70x10-5 T/s). The coil is connected to a 700- 2 resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. ↓ Y Part A Find the magnitude of the induced emf in the coil as a function of time. 8.89-10-³ V +(8.00×105 V/s³ )³ E 279x102V +(6.28×105 V/s³ )³ E=2.79×102 V +(2.51*10-4V/s³ )³ E-8.89-10³ V +(2.51*10-4 V/s³ )3 Submit Previous Answers Correct Part B What is the current in the resistor at time to = 4.95 s? VE ΑΣΦ 1= 4.16 10 5 Submit Previous Answers Request Answer X Incorrect; Try Again ? A

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter32: Faraday’s Law Of Induction
Section: Chapter Questions
Problem 63PQ
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A coil 4.20 cm radius, containing 420 turns, is
placed in a uniform magnetic field that varies with
time according to B=( 1.20x10-2 T/s)t+(
2.70x10-5 T/s). The coil is connected to a 700-
2 resistor, and its plane is perpendicular to the
magnetic field. You can ignore the resistance of the
coil.
↓
▼
Part A
Find the magnitude of the induced emf in the coil as a function of time.
8.89×10³ V +(8.00-10-5 V/s³ )³
ⒸE=2.79×10 2 V +(6.28×10-5 V/s³ )t³
E = 2.79×10² V +(2.51×10-4 V/s³ )t³
£ 8.89-10 ³ V +(2.51×10 4 V/s³ )t3
Submit
Previous Answers
✓ Correct
Part B
What is the current in the resistor at time to = 4.95s ?
ΑΣΦ
1= 4.16 107
Submit Previous Answers Request Answer
X Incorrect; Try Again
A
Transcribed Image Text:A coil 4.20 cm radius, containing 420 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20x10-2 T/s)t+( 2.70x10-5 T/s). The coil is connected to a 700- 2 resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. ↓ ▼ Part A Find the magnitude of the induced emf in the coil as a function of time. 8.89×10³ V +(8.00-10-5 V/s³ )³ ⒸE=2.79×10 2 V +(6.28×10-5 V/s³ )t³ E = 2.79×10² V +(2.51×10-4 V/s³ )t³ £ 8.89-10 ³ V +(2.51×10 4 V/s³ )t3 Submit Previous Answers ✓ Correct Part B What is the current in the resistor at time to = 4.95s ? ΑΣΦ 1= 4.16 107 Submit Previous Answers Request Answer X Incorrect; Try Again A
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