A common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight. Suppose that the percentage of no-shows at flight time is 3%. For a particular flight with 170 seats, a total of 175 tickets were sold. What is the probability that the airline overbooked this flight? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table, The probability is (Round to four decimal places as needed.)

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A: We have given that.   X~N( μ , ?^2 )   μ =139 , ? =26.7  ,n=37   Z-score =( x - μ )/?

Q: The mean of a standard normal probability distribution

A:

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A: Solution

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A:

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.