A company that manufactures lamps has a fixed cost of $80,000 and it costs $20 to produce each lamp. Lamps are sold for $70. a. Write the cost function. C(x) = 80,000 + 20x Fixed Variable cost: cost $20 per lamp b. Write the revenue function. R(x) 70x Revenue per lamp, $70, times number of lamps sold c. Find the break-even point. Solve Sy 80,000 + 20x 70x by substitution. Solving 70x = 80,000 + 20x yields x = 1600. Back-substituting, y The break-even point is (1600, 112,000): The company breaks even if it sells 1600 lamps. At this level, money coming in equals money going out: $112,000. 112,000.
A company that manufactures lamps has a fixed cost of $80,000 and it costs $20 to produce each lamp. Lamps are sold for $70. a. Write the cost function. C(x) = 80,000 + 20x Fixed Variable cost: cost $20 per lamp b. Write the revenue function. R(x) 70x Revenue per lamp, $70, times number of lamps sold c. Find the break-even point. Solve Sy 80,000 + 20x 70x by substitution. Solving 70x = 80,000 + 20x yields x = 1600. Back-substituting, y The break-even point is (1600, 112,000): The company breaks even if it sells 1600 lamps. At this level, money coming in equals money going out: $112,000. 112,000.
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.CR: Review Problem Set
Problem 50CR
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