A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively. Stationing at the point of compound curve is at 11+135.92m. Degrees of curve are 3°30' and 4°00 for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall end with the same P.C. Determine the: a. Total length of the simple curve b. Station the Old P.C. and the New P.T.

A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively. Stationing at the point of compound curve is at 11+135.92m. Degrees of curve are 3°30' and 4°00 for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall end with the same P.C. Determine the: a. Total length of the simple curve b. Station the Old P.C. and the New P.T.

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 7P

See similar textbooks

Similar questions

Determine the total length of the compound curve if the central angle of the simple curves are 53°54’ & 30°00’ respectively with radii of 200 & 290 m, respectively
A compound curve is laid out 480 m. from the P.C. to the P.C.C. having a radius of 763.94 m then from the P.C.C another curve was laid out to the P.T. 250 m long with a radius of 208.85 m. If the stationing of the point of intersection of the tangents is 10 + 432.25. a. Determine the stationing of the P.C b. Determine the length of the long chord from the P.C. to the P.T. c. Determine the angle that the long chord makes with the tangent
An unsymmetrical parabolic curve has a forwardtangent of -8% and a back tangent of +5%. Thelength of the curve on the left side (P.C.) is60 m and the vertex is at elevation of 100 m.The elevation of the road just below the vertexis 97.3. Calculate the total length of theunsymmetrical curve.
The vertex of a 5°30’ simple curve is at station 3+007.220 whose central angle is 60°. The simple curvemust be connected by a 3°30’ simple curve to meet the location of the new P.T. which is 15m offset fromthe existing P.T. remaining the location of the P.C.a) Solve for the new central angle of the first curveb) Solve for the station of the PCCc) Solve for the station of the new PT
Two tangents intersecting at V with bearings N 75o12’ E and S 78o36’ E are connected with a 3.5-degree simple curve. Without changing the direction of the two tangents and with the same angle of intersection, it is required to shorten the curve to 110 m starting from PC. By how much shall the point of the intersection of the tangent be moved in meters? ["", "", "", "", "", "", "", "", "", ""] Determine the distance between the old and new forward tangents in meters. ["", "", "", "", "", "", "", "", "", ""] By how much shall the PT be moved from the old tangent?
the length of a parabolic curve is 130m. the forward tangent has a slope of 2.6%. back tangent has a slope of - 2.5%. Compute the distance of the lowesr point of the curve from the P. C
Two tangents intersect at station 2 + 550. A compound curve laid on their tangents has the following data. I1 = 310, I2 = 360, D1 = 30, D2 = 50 a) Compute the stationing of the P.C., P.C.C. of the curve. b) If the P.T. is moved 15 m out, compute the station of the P.T. with the P.C.C. on the same point.
A vertical sag parabolic curve has a length of curve of 420 m. from A to B. The back tangent has a slope of −3.2% and the point of intersection of the tangents is at station 7 + 180 with an elevation of 998 m. Find the elevation of point A.
A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively. The length of the chord is 340m long measured from the P.C to the P.T of the curve and is parallel to the common tangent having an azimuth 270 °. If the stationing of P.T is 6+000 a) Plot the compound curve b) Compute all of the elements of a compound Curve. c) Determine the stationing by the interval of 20 of the curve
1. A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54 m from PC. The elevation of PC at Station 4+382.3 is 22.56 m. The grade of the back tangent is +(9÷3)% and the length of the curve is 120 m. a. Compute the grade of the forward tangent. b. Compute the stationing of the highest point of the curve. c. Compute the elevation of the highest point of the curve.
A compound curve with R1=390.32 m, R2=174.20 m has a central angle of 12° and 20°, respectively.The station PI is at 7+350.Determine the length of long chord, station PC, PCC, and PT, if the long chord is parallel to the commontangent.
The slope of the forward tangent of a parabolic curve is +4.2%, while the slope of the back tangent is -3.6%. The length of the curve is 120m long with elevation of the PC equal to 82.77. Determine the elevation of the curve directly above the PI.