A computer system is designed so that if component C1 fails, it is bypassed and C2 is used. If C2 fails, then it is bypassed and component C3 is used. If C3 fails, then it is bypassed and Component C4 is used. The system fails only if all 4 components fail. The failure of any of the four components is independent of the failure of any of the other components. There is a .4 probability that C1 fails, a .4 probability that C2 fails, a .3 probability that C3 fails and a .2 probability that C4 fails a. What is the probability C1, C2, C3, and C4 all fail? b. What is the probability none of C1, C2, C3, or C4 fail? c. What is the probability that the system works (does not fail)? d. What is the probability that C1 and C3 fail? e. What is the probability that C1 or C3 fails? f. What is the probability that exactly one of the components works?
A computer system is designed so that if component C1 fails, it is bypassed and C2 is used. If C2 fails, then it is bypassed and component C3 is used. If C3 fails, then it is bypassed and Component C4 is used. The system fails only if all 4 components fail. The failure of any of the four components is independent of the failure of any of the other components. There is a .4 probability that C1 fails, a .4 probability that C2 fails, a .3 probability that C3 fails and a .2 probability that C4 fails a. What is the probability C1, C2, C3, and C4 all fail? b. What is the probability none of C1, C2, C3, or C4 fail? c. What is the probability that the system works (does not fail)? d. What is the probability that C1 and C3 fail? e. What is the probability that C1 or C3 fails? f. What is the probability that exactly one of the components works?
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter2: Matrices
Section2.5: Markov Chain
Problem 16E: Consumer Preference In a population of 100,000 consumers, there are 20,000 users of Brand A, 30,000...
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