A conductor (red sphere) is placed in constant electric field pointing from left to right as shown below. In presence of theelectric field, the electrons in the conductor will move around and polarize the conductor. After equilibrium is reached, thecharges on the conductor will have the following configuration:the conductor will not be polarizedpositive charges will settle to the left and negative to the right of the conductorpositive and negative charges will be equally distributed everywhereO positive charges will settle to the right and negative to the left of the conductor

The electric field within the conductor is always zero.

A conductor (red sphere) is placed in constant electric field pointing from left to right as shown below. In presence of the electric field, the electrons in the conductor will move around and polarize the conductor. After equilibrium is reached, th charges on the conductor will have the following configuration:

A conductor (red sphere) is placed in constant electric field pointing from left to right as shown below. In presence of the electric field, the electrons in the conductor will move around and polarize the conductor. After equilibrium is reached, th charges on the conductor will have the following configuration:

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 68PQ: Examine the summary on page 780. Why are conductors and charged sources with linear symmetry,...

See similar textbooks

Similar questions

Examine the summary on page 780. Why are conductors and charged sources with linear symmetry, spherical symmetry, and planar symmetry categorized as special cases rather than major concepts or underlying principles?
There are electric charges in a certain region of space. In cylindricalcoordinates (r,theta, z ) the distribution of charges is characterized as pv = 5re^- r (C/m3 )Find the electric field E induced by the charges. Thank you for the help on this question.
Imagine that two parallel plates are charged to achieve a voltage difference Vo between the plates. They have area A and spacing d. The plates are then electrically isolated so that no charge can be added or taken away. A good conductor of thickness d/2 is placed in between the two plates, as shown. Given that the charge on the plates cannot change, what is the electric field in the regions between the plates, but above and below the conductor? (If you are stuck, Gauss’s Law may help.)
Calculate the electric field at the center of a dielectric cylinder of circular cross-section of height h and radius a with a permanent uniform polarization P0 perpendicular to its circular faces.
An (ideal) electric dipole of magnitude p = 1 × 10−6 C·m is placed ata distance a = 0.05 m away from the center of an uncharged, isolated spherical conductor of radiusR = 0.02 m. Suppose the angle formed by the dipole vector and the radial vector (the vector pointingfrom the sphere’s center to the dipole’s position) is θ = 20o. Find the (electrostatic) interaction energybetween the dipole and the charge induced on the spherical conductor
Consider the charge distribution provided below. Given the position and sign (+ or -) of the two charges, what is the resulting direction (as shown by the large arrow) of the combined electric field at point P? a. Green b. Red c. Black d. Blue e. None of these
Find the electric field at P in the figure shown below. (Take r = 1.2 m and theta = 41degrees. Measure the angle counterclockwise from the positive x-axis.) magnitude direction
A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through.Randomized VariablesE = 2.7 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.7 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.
An electron has an initial velocity of 3×10to6 m/s in the +x direction. It enters a uniform electric field E = 418 N/C which is in the +y direction. By how much, and in what direction, is the electron deflected after traveling 11 cm in the +x direction in the field? (Express the direction of deflexion by using positive and negative signs. Your result must be in cm's and include 1 digit after the decimal point. Maximum of 5% of error is accepted in your answer. Take elementary charge 1.6x10to-19 C and mass of electron 9.1x10-31 kg.)
Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.
A charge q is placed in the cavity of a conductor as shown below. Will a charge outside the conductor experience an electric field due to the presence of q? The conductor in the preceding figure has an excess charge of -5.0 uC. If a 2.0 uC point charge is placed in the cavity, what is the net charge on the surface of the cavity and on the outer surface of the conductor?
We have the electric field: E = 5xx + 2y + (4/π)z. (a) Calculate its flow through the three surfaces S1, S2, S3 of the figure. The S3 measure is the fourth of the surface area of a unit radius and center that coincides with the beginning of the axes. (b) If there are no loads in the space, calculate the flow of E from the curvilinear surface. (ni, x, y, z are unit vectors)