A cylinder of length 80.0cm and diameter 30.0cm has its concident with the x axis. The electric field in this region is E=(250i)N/C as shown in figure 1. Compute the electric flux through the (i)left end of the cylinder.(ii)right end of the cylinder.(iii) cylinder wall.Figure 1 A cylinder of length 80.0 cm and diameter 30.0 cm has its axis coincident with the x axis. The electricfield in this region is Ē = (250i)N /C as shown in Figure 1. Compute the electric flux through the

Write the formula for the electric flux.

Answered: A cylinder of length 80.0cm and…

A cylinder of length 80.0cm and diameter 30.0cm has its concident with the x axis. The electric field in this region is E=(250i)N/C as shown in figure 1. Compute the electric flux through the

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter15: Fluids

Section: Chapter Questions

Problem 68PQ

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A cylinder of length 80.0cm and diameter 30.0cm has its concident with the x axis. The electric field in this region is E=(250i)N/C as shown in figure 1. Compute the electric flux through the

(i)
left end of the cylinder.
(ii)
right end of the cylinder.
(iii) cylinder wall.
Figure 1

A cylinder of length 80.0 cm and diameter 30.0 cm has its axis coincident with the x axis. The electric
field in this region is Ē = (250i)N /C as shown in Figure 1. Compute the electric flux through the

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