Question
Asked Oct 12, 2019
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A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 27.5 m/s. A net is positioned a horizontal distance of 52.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil? 

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Expert Answer

Step 1

Given:

Angle of firing of cannon = 45 degrees

Initial speed of the cannon = 27.5 m/s

Horizontal position of the net = 52 m

Step 2

Calculating the vertical position of t...

Equation of trajectory of the projectile
1 g
2 u cos e
yxtan e
Here, u is the initial velocity, x is the horizontal position and y is vertical position
Substituting given values
1 (9.8m/s2(52m)
2 (27.5m s) cos
y(52m) tan(45)
(45)
(9.8) x (2704)
y=(52m)(1 x-
(756.25)x
y52m-35m=17m
y17m
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Equation of trajectory of the projectile 1 g 2 u cos e yxtan e Here, u is the initial velocity, x is the horizontal position and y is vertical position Substituting given values 1 (9.8m/s2(52m) 2 (27.5m s) cos y(52m) tan(45) (45) (9.8) x (2704) y=(52m)(1 x- (756.25)x y52m-35m=17m y17m

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