A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T. What is the radius of the resulting circular path? (deuteron: m = 3.3 10-27 kg, q = 1.6 ´ 1019 C) а. 10 mm b. 19 mm c. 13 mm d. 9.0 mm e. 20 mm

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter4: The Particle Nature Of Matter
Section: Chapter Questions
Problem 3P: A mystery particle enters the region between the plates of a Thomson apparatus as shown in Figure...
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5.6
1:01 IO 21%}0
4.ll Orange JO
K/s
A deuteron is accelerated from rest through
a 10-kV potential difference and then moves
perpendicularly to a uniform magnetic field
with B = 1.6 T. What is the radius of the
resulting circular path? (deuteron: m
= 3.3
10-27 kg, q = 1.6 ´ 1019 C)
a. 10 mm
b. 19 mm
с. 13 mm
d. 9.0 mm
e. 20 mm
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Transcribed Image Text:5.6 1:01 IO 21%}0 4.ll Orange JO K/s A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T. What is the radius of the resulting circular path? (deuteron: m = 3.3 10-27 kg, q = 1.6 ´ 1019 C) a. 10 mm b. 19 mm с. 13 mm d. 9.0 mm e. 20 mm Previous page Next page - Sunday 20/12 Class Jump to... Quiz VI
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