A differential equation y dx+ (x³y²+x²)dy = 0 js separated to obtain: A x'dx= (y²+ 1) dy B x-³dx= dy x³dx= (y+ ÷)dy y x-³dx= (y²– 1) dy

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A differential equation y dx+ (x³y²+x³) dy = 0 is separated to obtain:
A x*dx= (y²+1)dy
x-³dx = -
x³dx = (y+ ÷)dy
y
D
x-³dx= (y² – 1) dy
B.
Transcribed Image Text:A differential equation y dx+ (x³y²+x³) dy = 0 is separated to obtain: A x*dx= (y²+1)dy x-³dx = - x³dx = (y+ ÷)dy y D x-³dx= (y² – 1) dy B.
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