Using the substitutions 2= sin y and dz=cos y dy, the differential equation (3sin y – 5x)dx +2x² cot y dy=0 reduces to A z(3z - 5x) dx + 2x² dz = 0 B (3z - 5x) dx + 2x² dz =0 (3z- 5x) dx – 2x² dz = 0 z(3z - 5x) dx - 2x? dz = 0

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A: We will find out the required solution.

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