A diverging lens with a focal length -12.0 cm is to the left of a mirror with a focal3)length of 20 cm. There is a real object a distance of 4.0 cm to the left of the lens. The distancebetween the lens and the mirror is 1.0 cm.Ycmobectleasa) What is the radius of curvature of the mirror?b) Is the mirror concave or convex?c) There are a sequence of images produced as light passes through the lens, reflects off of the mirrorand goes back through the lens. Where is the final image?d) What is the magnification of the final image?e) Is the final image real or virtual? Is it upright or inverted?(Hint: The distances are all integer numbers of cm. This should tell you if you make a mistake.

According to Guidelines, I can solve first three parts of the question. If you need help with other…

Answered: A diverging lens with a focal length…

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter25: Optical Instruments

Section: Chapter Questions

Problem 24P: A jewelers lens of focal length 5.0 cm is used as a magnifier. With the lens held near the eye,...

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Similar questions

A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.50 mm. With the length of the barrel set at 29.0 cm, the diameter of a red blood cells image subtends an angle of 1.43 mrad with the eye. It the final image distance is 29.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this question, go back to basics and use the thin-lens equation.
What is the focal length of a makeup mirror that produces a magnification of 1.50 when a person’s face is 12.0 cm away? Explicitly show how you follow the steps in the Problem-Solving Strategy: Spherical Mirrors.
A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.
. A small object is placed to the left of a convex lens and on its optical axis. The object is 30 cm from the lens, which has a focal length of 10 cm. Determine the location of the image formed by the lens. Describe the image.
A jewelers lens of focal length 5.0 cm is used as a magnifier. With the lens held near the eye, determine (a) the angular magnification when the object is at the focal point of the lens and (b) the angular magnification when the image formed by the lens is at the near point of the eye (25 cm). (c) What is the object distance giving the maximum magnification?
A virtual image is formed 20.0 cm from a concave mirror having a radius of curvature of 40.0 cm. (a) Find the position of the object. (b) What is the magnification of the mirror?
Use the law of reflection to prove that the focal length of a mirror is half its radius of curvature. That is, prove that f = R/2. Note this is true for a spherical mirror only if its diameter is small compared with its radius of curvature.
Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height? Figure 25.50 A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it.
Will the focal length of a lens change when it is submerged in water? Explain.

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