A drone is programmed so that its horizontal and vertical components of position as functions of time t (seconds) are given by x(t) = 2t2 and y = -t3 + 8t2 – 5t +4 respectively. (a) What are the magnitude and direction of the instantaneous velocities at t = 0 and t %3D 4 sec? (b) Find the time at which the drone attains maximum height and also find the maximum height attained by the drone.

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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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A drone is programmed so that its horizontal and vertical components of position
as functions of time t (seconds) are given by x(t) = 2t2 and y = -t3 + 8t2 – 5t +4
respectively.
(a) What are the magnitude and direction of the instantaneous velocities at t =
0 and t
%3D
4 sec?
(b) Find the time at which the drone attains maximum height and also find the
maximum height attained by the drone.
Transcribed Image Text:A drone is programmed so that its horizontal and vertical components of position as functions of time t (seconds) are given by x(t) = 2t2 and y = -t3 + 8t2 – 5t +4 respectively. (a) What are the magnitude and direction of the instantaneous velocities at t = 0 and t %3D 4 sec? (b) Find the time at which the drone attains maximum height and also find the maximum height attained by the drone.
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