F1 = 250 lbx = 6 fty = 2 fta = 3b = 2Total Moment = 400 lb-ft (counterclockwise)Find the perpendicular moment arm of F (in ft). Find F (in lb). -F16aF1yF1Fa

Given, F1= 250 lb x = 6 ft y = 2 ft a = 3 b = 2 Total M = 400 lb-ft

Answered: a F1 y F1 1b F a

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

F1 = 250 lb
x = 6 ft
y = 2 ft
a = 3
b = 2
Total Moment = 400 lb-ft (counterclockwise)

Find the perpendicular moment arm of F (in ft).
Find F (in lb).

Expert Solution

Step 1

Given,

F₁= 250 lb

x = 6 ft

y = 2 ft

a = 3

b = 2

Total M = 400 lb-ft

Step 2

For couple forces, moment at any point is equal to the product of force and perpendicular distance between them.

Let d be the perpendicular distance between couple force F.

Step 3

$M d u e t o c o u p l e F (C o u n t e r c l o c k w i s e) - M d u e t o c o u p l e F_{1} (C l o c k w i s e) = T o t a l M (c o u n t e r c l o c k w i s e) F d - F_{1} y = 400 l b . f t F d - (250) (2) = 400 F d = 900 l b . f t . . . . (1)$

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