(a) Find the probability mass function, p(x) = P(X = x). (b) Find the expected value, variance and the standard deviation of X.
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Let X be the discrete random variable with the cumulative distribution
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- Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?Altmans z-score Altmans z-score is a financial tool for predicting insolvency in a business. For a certain company, the z-score formula is z=0.84+0.6StockpriceOutstandingsharesTotalliabilty In this exercise, we assume that thre are 45, 000 outstanding shares at a price of 4.80 each. a. Use L, for total liability, in dollard, and give a formula for the z-score for this company. b. Would a larger total liability idicate a better or worese outlook for the company? c. A z-score of 1.81 or lower indicates a high probability of insolvency. What is the smallest value of L that will give a z-score that indicates a high probability on insolvency?Find the conditional expectation E(Y/X=0.47) if the joint probability density function of the random variable X and Y isf(x, y) = 1/x, 0 < y ≤ x ≤ 1.
- 2.1 The demand for a product varies from month to month. Based on data from past years, the following probability density function shows the probabilities of MNM company’s monthly demand. Probabilities of MNM company's monthly demand Unit Demand P(X=x) 1200 0.19 2100 0.30 3300 0.40 3800 0.11 a) What is the probability that MNM will sell 3300 units next month? b) Given the information above, how many units can they expect to sell in a month?2.2 The demand for a product varies from month to month. Based on data from past years, the following probability density function shows the probabilities of MNM company’s monthly demand. Probabilities of MNM company's monthly demand Unit Demand P(X=x) 1200 0.19 2100 0.30 3300 0.40 3800 0.11 c) Calculate the standard deviation. d) Each unit produced costs the company $8.00, and each unit is sold for $25.00. How much will the company gain or lose in a month if they stock the expected number of units demanded but sell 2100 units?The cumulative distribution function F(x) of a discrete random variable X is given by F(0) = .30, F(1) = .70, F(2) = .90, and F(3) = 1.0, then the value of the probability mass function p(x) at x = 1 is what?
- A random variable X has the following probability mass function table X 0 1 2 probability 0.25 0.5 0.25 What is E[X2 − X]? Compute E[2X].An insurance company sells life insurance of GH₵15,000.00 for a premium of GH₵310.00 per year. Actuarial tables show that the probability of death in the year following the purchase of the policy is 0.1%. What is the expected gain for this type of policyThe General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.04 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.03 0.04 0.03 0.02 Find ρ(X, Y). (Round the final answer to four decimal places.) ρ(X, Y) =
- The General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.03 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.04 0.04 0.03 0.02 Find the conditional expectation E(Y|X = 4). (Round the final answer to four decimal places.)The General Social Survey asked a sample of adults how many siblings (brothers and sisters) they had (X) and also how many children they had (Y). We show results for those who had no more than 4 children and no more than 4 siblings. Assume that the joint probability mass function is given in the following contingency table: y x 0 1 2 3 4 0 0.03 0.01 0.02 0.01 0.01 1 0.09 0.05 0.08 0.03 0.01 2 0.09 0.05 0.07 0.03 0.02 3 0.06 0.04 0.07 0.04 0.02 4 0.04 0.04 0.04 0.03 0.02 Find the conditional probability mass function pY|X(y|4). (Round the final answer to four decimal places.) pY|X(0|4) = pY|X(1|4) = pY|X(2|4) = pY|X(3|4) = pY|X(4|4) = Find the conditional probability mass function pX|Y (x|3). (Round the final answer to four decimal places.) pX|Y(0|3) = pX|Y(1|3) = pX|Y(2|3) = pX|Y(3|3) = pX|Y(4|3) = Find the conditional expectation E(X|Y = 3). (Round the final answer to four decimal places.) E(X|Y = 3) =The lung cancer hazard rate λ(t) of a t-year-old male smoker is such that λ(t) = 0.027 + 0.00025(t-40)2, and t >= 40. Assuming that a 40-year-old male smoker survives all other hazards, (a) what is the probability that he survives to age 50 without contracting lung cancer?(b) what is the probability that he survives to age 60 without contracting lung cancer?
