(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. 1,599,900 x w (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? cents

University Physics Volume 1
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Chapter7: Work And Kinetic Energy
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Problem 76P: Calculate the power output needed for a 950-kg car to climb a 2.00 slope at a constant 30.0 m/s...
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(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the
counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated.
1,599,900 x w
(b) What does it cost (in cents), if electricity is $0.0900 per kW · h?
cents
Transcribed Image Text:(a) Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2600 kg is raised in height, but the full 10,000 kg is accelerated. 1,599,900 x w (b) What does it cost (in cents), if electricity is $0.0900 per kW · h? cents
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