A fish swimming in a horizontal plane has velocity v = ((4.00)î + (1.00)f)m/s at a point in the ocean where its position relative to a certain rock is r = ((10.0)î – (4.00)f)m. After the fish swims with constant acceleration for 20.0 s, its velocity becomes v ((20.0)-(5.00)f)m/s. What are the horizontal and vertical components of the acceleration (in m/s2)? %3D O a. -1.4, 2.9 ОБ.1.4, 2.6 Ос. -0.3, 0.8 Od.0.8, -0.3 De. 2.4, -1.5

A fish swimming in a horizontal plane has velocity v = ((4.00)î + (1.00)f)m/s at a point in the ocean where its position relative to a certain rock is r = ((10.0)î – (4.00)f)m. After the fish swims with constant acceleration for 20.0 s, its velocity becomes v ((20.0)-(5.00)f)m/s. What are the horizontal and vertical components of the acceleration (in m/s2)? %3D O a. -1.4, 2.9 ОБ.1.4, 2.6 Ос. -0.3, 0.8 Od.0.8, -0.3 De. 2.4, -1.5

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Description: uestion Completion Status:A fish swimming in a horizontal plane has velocity vị = ((4.00)î + (1.00)ĵ)m/s at a point in the ocean where its positionrelative to a certain rock is T= ((10.0)î –- (4.00)j)m. After the fish swims with constant acceleratio

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 3P: A particle initially located at the origin has an acceleration of a=3.00jm/s2 and an initial...

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