A flanged bolt coupling consists of six 20- mm diameter steel bolts spaced evenly around a bolt circle x mm in diameter. The torque capacity of the coupling is 9.42 kNm and the shearing stress in the bolts is not to exceed 40 MPa. Determine the value of x. Select one: Oa. 200 mm O b. 300 mm O c. 250 mm O d. 280 mm
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- A flanged bolt coupling consists of eight ½ -in. steelbolts evenly spaced around a bolt circle 12 in. indiameter, and six ¾ -in. aluminum bolts on aconcentric bolt circle 8 in. in diameter. What torquecan be applied without exceeding 15000 psi in thesteel or 10000 psi in the aluminum? Assume Gst =12 × 106 psi and Gal = 4 × 106 psi.Pls answer thank you! A flange bolt coupling has 10 steel coupling 1 inch diameter bolts evenly tighten around a 16.34 in. bolt circle. Determine the torque capacity of the connection if the allowable shearing stress in the bolt is 7.3 ksi?8. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksih) what is the flexural rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)
- A flanged bolt coupling consists of six ½-in. steel bolts evenly spaced around a bolt circle 12 in. in diameter, and four ¾-in. aluminum bolts on a concentric bolt circle 8 in. in diameter. What torque can be applied (kip-in) without exceeding 9000 psi in the steel or 6000 psi in the aluminum? Assume Gst = 12 × 106 psi and Gal = 4 × 106 psi.an angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kNThe unbraced column length of Round HSS 18 x0.5 in A500 Grade C (Fy = 50 ksi) is 30 ft.Determine the design compressive strength of the column using the equations in Chapter E inPart 16 of the AISC Manual. Confirm your answer using the AISC Manual Table 4-5 (pages 4-84,New AISCM) and (pages 4-84, New AISCM). The column has pin supports at both ends ( i.e Kx= Ky = 1.0) columns. Lx = Ly = 30 ft
- 5. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi e) what is the shear rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)The given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. plate: fy = 241 mpa fu = 4141 mpa rivet: fv = 152 mpa a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivetspls help! Write the complete solutions and legibly. Answer in 2 decimal places. UPVOTE WILL BE GIVEN! MECHANICS OF DEFORMABLE BODIES Let Q = 0 and T = 8 (Example: 12Q°C = 120°C). Just substitute the number in letter. Thank you! For the frame shown, a 4QQT-N load is acting on member ABD at D. If the allowable material shear stress for is 4Q MPa, determine the required diameter (rounded off to the nearest 2.5 mm) of the pins at C and D. Pin C and pin D are subjected to double shear and single shear, respectively. If the thickness of member BC is 12 mm and that of member DE is 16 mm, determine the maximum bearing stress at C.
- A flanged bolt coupling consists of six 1/2-in. steel bolts evenly spaced around a bolt circle 12 in. in diameter, and four 3/4-in. aluminum bolts on a concentric bolt circle 8 in. in diameter. What torque can be applied without exceeding 9000 psi in the steel or 6000 psi in the aluminum? Assume Gst = 12 x 10^6 psi and Gal = 4 x 10^6 psi.6. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi f) what is the block shear rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)Determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi d) what is the shear yielding capacity of the shear plate of the shear connection in kips? (2 decimal places)