48. A flat cushion of massQC released from rest at the corner ofm isCushionthe roof of a building, at height h.A wind blowing along the side ofWindforcethe building cxcrts a constanthorizontal force of magnitude Fon the cushion as it drops asshown in Figure P5.48. The airhexerts no vertical force. (a) Showthat the path of the cushion is astraight line. (b) Does the cushionwithExplain. (c) If m =8.00 m, and F= 2.40 N, how far from the building will thecushion hit the level ground? What If? (d) If the cushion isthrown downward with a nonzero speed at the top of the build-ing, what will be the shape of its trajectory? Explain.velocity?1.20 kg, h =fallconstantFigure P5.48

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A flat cushion of mass m is o Cu released from rest at the corner of Wind force the roof of a building, at height h. A wind blowing along the side of the building cxcrts a constant horizontal force of magnitude F on the cushion as it drops as shown in Figure P5.48. The air exerts no vertical force. (a) Show

A flat cushion of mass m is o Cu released from rest at the corner of Wind force the roof of a building, at height h. A wind blowing along the side of the building cxcrts a constant horizontal force of magnitude F on the cushion as it drops as shown in Figure P5.48. The air exerts no vertical force. (a) Show

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 42P

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