A force É = (4.40 N) î + (3.00 N)ĵ+ (1.80 N) k acts on a 5.40 kg mobile object that moves from an initial position of d; = (4.90 m) î + (3.50 m)ĵ + (5.90 m) Ê to a final position of á = (3.20 m) î + (6.60 m)ĵ + (5.10 m) k in 2.20 s. Find (a) the work done on the object by the force in the 2.20 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d ; and d f.

A force É = (4.40 N) î + (3.00 N)ĵ+ (1.80 N) k acts on a 5.40 kg mobile object that moves from an initial position of d; = (4.90 m) î + (3.50 m)ĵ + (5.90 m) Ê to a final position of á = (3.20 m) î + (6.60 m)ĵ + (5.10 m) k in 2.20 s. Find (a) the work done on the object by the force in the 2.20 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d ; and d f.

Name: A force F = (4.40 N) î + (3.00 N)ĵ + (1.80 N) k acts on a 5.40 kg mob
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Description: A force F = (4.40 N) î + (3.00 N)ĵ + (1.80 N) k acts on a 5.40 kg mobile object that moves froman initial position of á ; = (4.90 m) î + (3.50 m)ĵ + (5.90 m) k to a final position ofd; = (3.20 m)î + (6.60 m)ĵ + (5.10 m) k in 2.20 s. Find (a) the wor

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Conservation Of Energy

Section: Chapter Questions

Problem 8.78AP

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