A force is specified by the vector F = 120i + %3D 160j + 80k Ib. - Determine the length of the vector. - What would be the cross product of vector F with vector A=2i + 6j + 8k
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- Determine the algebraic sum of the moments of forces relative to a point in F = 10.0 N; m =9.0 Nm, q =8.0 N/m1. Determine the resultant of the three concurrent forces. y F=50N F=10N 14 60° X F=60N 2. [Example] A hand crankFi is in the Axy plane. A force F is applied at point D and in a plane perpendicular to the y axis. The angle between the force and the vertical line is a. CD=a, BCllx, CD/ly, AB-BC=1. Determine the moments of the force about x, y and z axes. E A yExpiremental Method: Force Table F1 - 150N, 30° N of E F2 - 100N, 60° E of S 1) Find the Equilibrant Magnitude and Equilibrant Direction 2) Find Resultant Force Vector Magnitude and %Error 3) Find Resultant Force Vector Direction and %Error
- Two forces in the x and y directions are given as 5.451 kN and 3.279 kN, respectively. What is the resultant force? Question 15Answer a. 7.45 N b. 7458 N c. 4.341 N d. 6361 N e. 6.31 NThe resultant of four coplanar, concurrent forces is 600 lb, directed S 40 E. Three of the forces are 500 lb, directed NW,; 400 lb, directed E; and 300 lb directed S. • What is the x-component of the fourth force?S Ans. 339.22 lb • What is the y-component of the fourth force? Ans. 513.18 downward • What are the magnitude and direction of the fourth force? Ans. 615.16 lb 56.53° S of E need solution and sketch thankyouVerify if my answers are correct:R=6kNd=1.875 mHence the resultant force will act at 1.875m away from point A.
- What is the equivalent resultant force and specify its location, measured from point 0 Choices: FR= 12.5 kN, d= 1.54 m FR= 13.5 kN, d= 1.44 m FR= 12.5 kN, d= 1.64 m FR= 13.5 kN, d= 1.54 mThree forces intersect at point (1, 1, 1). Their magnitude and respective second point of incidence are as follows: 450 lbs (4, -3, 7), 600lbs (-1, 5, -4), 300lbs (-3, 6, -2) 1. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 2. Compute the direction cosine on the y-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 3. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513Consider the given values for the force system shown: xA = 9 ft xB = -12 ft xC = 7 ft yA = 3 ft yB =10 ft yC = 2 ft zA = 1 ft zB = -9 ft zC = 11 ft A. Determine the angle θ between AB and AC. B. Determine the minimum distance from point B that passes through AC.
- Determine the intensity and position of the resultant R lf two forces F1 and F3 and torque M that acts on the metal profile given as in the figure,if: F1= 2kN a=2,10m F2= 5kN b=2,10m M=24kNm c=3,10m18 - Exspress the resultant force of the three forces as a vector form. Which following one is TRUE? unit vectors are i, j, k.A) Resultant force: (4 - 5.cos45 + 8.cos75).i + (5.sin45 - 8.cos75).jB) Resultant force: (5 + 4.cos45 - 8.cos75).i + (4.sin45 + 8.sin15).jC) Resultant force: (8 + 5.cos45 - 4.cos75).i - (5.sin45 + 4.sin75).jD) Resultant force: (4 + 5.cos45 - 8.cos75).i + (5.sin45 + 8.sin75).jE) Resultant force: (4 - 5.cos45 + 8.cos75).i + (5.sin45 - 8.sin75).jA force F1= 2i – 6k {kN) is applied at the position 3j + 5k {m}, meanwhile another force F2 = - i + 4j + 7k {kN) is applied at the position 8k {m}, on a structure. Evaluate the resultant moment by vector calculation