A force of 25.0 N is applied in the positive x-direction to a block of mass 9.25 kg, at rest on a frictionless surface.HINT(a)What is the block's acceleration (in m/s2)? (Indicate the direction with the sign of your answer.)m/s2(b)How fast is it going (in m/s) after 5.00 s?m/s

Question
Asked Nov 1, 2019
A force of 25.0 N is applied in the positive x-direction to a block of mass 9.25 kg, at rest on a frictionless surface.
HINT
(a)
What is the block's acceleration (in m/s2)? (Indicate the direction with the sign of your answer.)
m/s2
(b)
How fast is it going (in m/s) after 5.00 s?
m/s
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Expert Answer

Step 1

Given,

F 25 N
m 9.25 Kg
t 5 sec
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F 25 N m 9.25 Kg t 5 sec

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Step 2

Part (a):

By Newton’s law of force,

F =ma
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F =ma

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Step 3

By substituting t...

F ma
25 (9.25)a
a 2.70 m/sec2
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F ma 25 (9.25)a a 2.70 m/sec2

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