Show that f(x) has a jump discontinuity at x = 7 by calculating the limits from the left and right at x = 7. A function f(1) is said to have a jump discontinuity at x = a if:1. limf() exists.2. limf(1) exists.3. The left and right limits are not equal.5x 8 if. r < 7Let f(a)1if z 7I+9Show that f(r) has a jump discontinuity at r = 7 by calculating the limits from the left and right at7.limf(x) -I 7limf(r) =I+7*

The given function,fx=5x-8if x<71x+9if x≥7

A function f(1) is said to have a jump discontinuity at z = a if: 1. lim f(x) exists. 2. lim f(x) exists. 3. The left and right limits are not equal. 5x 8 if. T<7 Let f(a) 1 if a 7 I+9 Show that f(x) has a jump discontinuity at r = 7 by calculating the limits from the left and right at 7. lim f(r) = I7 lim f(r) = I7*

A function f(1) is said to have a jump discontinuity at z = a if: 1. lim f(x) exists. 2. lim f(x) exists. 3. The left and right limits are not equal. 5x 8 if. T<7 Let f(a) 1 if a 7 I+9 Show that f(x) has a jump discontinuity at r = 7 by calculating the limits from the left and right at 7. lim f(r) = I7 lim f(r) = I7*

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter3: Functions

Section3.3: Rates Of Change And Behavior Of Graphs

Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...

See similar textbooks

Similar questions

Determine if the statemment is true or false. If the statement is false, then correct it and make it true. If the function f increases on the interval -,x1 and decreases on the interval x1,, then fx1 is a local minimum value.
If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local extremum offon (a,c) ?
Calculate the limit algebraically. (If an answer does not exist, enter DNE.) lim h→0 8h2 + h 3h2 + 3h - ________________ If the limit does not exist, say why. (If the limit does exist, so state.) -The limit does not exist because one side diverges to ∞ and the other side diverges to −∞. -The limit does not exist because only one of the left or right limits exists as a finite value. -The limit does not exist because the left and right limits exist but are not the same finite value. -The limit does not exist because it diverges to ∞ or −∞. -The limit does exist and is a finite number.
The limit of (xy-2y) / (x2+y2-4x+4) as (x,y) approaches (2,0) is solved and found out that it does not exist. Can we make this continuous by defining f(2,0) = k for some real value k? If yes, what could this value be? If no, why not?
Find the limit of (x^2)/((2^x)-1)) as x goes to 0.
lim g(t) as t --> -1, where g(t) = {2t + 1, if t > -1 or 5t^2, if t < -1} piecewisewhy is does the limit not exist here?
Let h(x) = (x2 - 2x - 3)/(x2 - 4x + 3). a. Make a table of the values of h at x = 2.9, 2.99, 2.999, and so on. Then estimate limx-->3 h(x). What estimate do you arrive at if you evaluate h at x = 3.1, 3.01, 3.001,......instead? b. Support your conclusions in part (a) by graphing h near c = 3 and using Zoom and Trace to estimate y-values on the graph as x--> 3.
Solve for A and B so that F(x) has a limit at both x=2 and x=4