Question
Asked Oct 30, 2019

A gas mixture contains 0.600  mol of N2, 0.150  mol of H2, and 0.200  mol of CH4. Calculate the pressure of the gas mixture and the partial pressure of each constituent gas if the mixture is in a 10.0  L vessel at 27.00°C.

 

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Expert Answer

Step 1

The pressure of the gas mixtur...

Given, N 0.600 mol
H 0.150mol
CH 0.200mol
Totalmoles n-(0.600+0.150+0.200)
0.950mol
Volume 10.0 L
Temperature 27.00 C 27.00+ 273 =300 K
PV =nRT
nRT_0.950x0.0821x300
P=
V
10.0
=2.34atm
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Given, N 0.600 mol H 0.150mol CH 0.200mol Totalmoles n-(0.600+0.150+0.200) 0.950mol Volume 10.0 L Temperature 27.00 C 27.00+ 273 =300 K PV =nRT nRT_0.950x0.0821x300 P= V 10.0 =2.34atm

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