A gaseous compound of phosphorus (P) and fluorine (F) was found to have a density of 3.50 g L' at a temperature of 25.0 °C and a prcssure of 740 torr. It was also found to consist of 35.2% P and 64.8% F in a volume of 1 L. Assume that the mass of the sample is 100.0 g. Determine a) (i) its empirical formula (ii) its molecular mass using its empirical formula stated in part (i) (iii) its molecular mass using ideal gas law (iv) its molecular formula. Explain why the molecular formula is same as empirical formula. Given that the molecular mass of P is 30.97 g mol·'; the molecular mass of F is 19 g mol'; 1 atm = 760 torr

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter10: Gases And Their Properties
Section: Chapter Questions
Problem 105IL: You have a gas, one of the three known phosphorus-fluorine compounds (PF3, PF3, and P2F4). To find...
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A gaseous compound of phosphorus (P) and fluorine (F) was found to have a density of 3.50 g
L' at a temperature of 25.0 °C and a pressurc of 740 tor. It was also found to consist of 35.2%
P and 64.8% F in a volume of 1 L. Assume that the mass of the sample is 100.0 g. Determine
a)
(i)
its empirical formula
(ii)
its molecular mass using its empirical formula stated in part (i)
(iii)
its molecular mass using ideal gas law
(iv) its molecular formula. Explain why the molecular formula is same as empirical
formula.
Given that the molecular mass of P is 30.97 g mol';
the molecular mass of F is 19 g mol';
1 atm = 760 torr
Transcribed Image Text:A gaseous compound of phosphorus (P) and fluorine (F) was found to have a density of 3.50 g L' at a temperature of 25.0 °C and a pressurc of 740 tor. It was also found to consist of 35.2% P and 64.8% F in a volume of 1 L. Assume that the mass of the sample is 100.0 g. Determine a) (i) its empirical formula (ii) its molecular mass using its empirical formula stated in part (i) (iii) its molecular mass using ideal gas law (iv) its molecular formula. Explain why the molecular formula is same as empirical formula. Given that the molecular mass of P is 30.97 g mol'; the molecular mass of F is 19 g mol'; 1 atm = 760 torr
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