A gaseous mixture of CO and CO2 having total volume 150 mL is passed through a tube containing excess of red hot charcoal to cause the following reaction: CO(g) + C(s) - 2CO(g) The volume increases to 250 mL. Identify the correct statement. (a) Original mixture contains 50% by moles CO. (b) Original

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Chapter8: Gases
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Problem 155CP: Methane (CH4) gas flows into a combustion chamber at a rate of 200. L/min at 1.50 atm and ambient...
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A gaseous mixture of CO and CO2 having total volume 150 mL is passed through a tube containing excess of red hot charcoal to cause the following reaction: CO(g) + C(s) - 2CO(g) The volume increases to 250 mL. Identify the correct statement. (a) Original mixture contains 50% by moles CO. (b) Original mixture contains 33.33% by moles CO. (c) Original mixture contains 33.33% by moles CO2. (d) Mole fraction of CO2 in the original mixture is 0.4.
A gaseous mixture of CO and CO2 having total
volume 150 mL is passed through a tube containing
excess of red hot charcoal to cause the following
reaction:
CO(g) + C(s) - 2CO(g)
The volume increases to 250 mL. Identify the correct
statement.
(a) Original mixture contains 50% by moles CO.
(b) Original mixture contains 33.33% by moles CO.
(c) Original mixture contains 33.33% by moles CO2.
(d) Mole fraction of CO2 in the original mixture is 0.4.
Transcribed Image Text:A gaseous mixture of CO and CO2 having total volume 150 mL is passed through a tube containing excess of red hot charcoal to cause the following reaction: CO(g) + C(s) - 2CO(g) The volume increases to 250 mL. Identify the correct statement. (a) Original mixture contains 50% by moles CO. (b) Original mixture contains 33.33% by moles CO. (c) Original mixture contains 33.33% by moles CO2. (d) Mole fraction of CO2 in the original mixture is 0.4.
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