(a) Given a 60.0 V battery and 14.00 and 72.00 resistors, find the current (in A) and power (in W) for each when connected in series.66ХАx wP14.00 = 0311172.00 =AP72.00 =W(b) Repeat when the resistances are in parallel.14.00 -AP14.00172.00P72.00Additional MaterialsReadingWAW

Answered: Image /qna-images/answer/23d9c27a-7fca-4eeb-bda1-a442856423e2.jpg

(a) Given a 60.0 V battery and 14.00 and 72.00 resistors, find the current (in A) and power (in W) for each when connected in series. 66 ХА x w P14.00 = 0311 72.00 = A P72.00 = W (b) Repeat when the resistances are in parallel. 14.00 = A P14.00 = 172.00 = P72.00 W A W

(a) Given a 60.0 V battery and 14.00 and 72.00 resistors, find the current (in A) and power (in W) for each when connected in series. 66 ХА x w P14.00 = 0311 72.00 = A P72.00 = W (b) Repeat when the resistances are in parallel. 14.00 = A P14.00 = 172.00 = P72.00 W A W

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter29: Direct Current (dc) Circuits

Section29.5: Resistors In Parallel

Problem 29.7CE

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Question

(a) Given a 60.0 V battery and 14.00 and 72.00 resistors, find the current (in A) and power (in W) for each when connected in series.
66
ХА
x w
P14.00 = 0311
172.00 =
A
P72.00 =
W
(b) Repeat when the resistances are in parallel.
14.00 -
A
P14.00
172.00
P72.00
Additional Materials
Reading
W
A
W

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