A glass rod forms a semicircle of radius R = 4.0 cm with a charge +q distributed uniformly along theleft quadrant and -q distributed uniformly along the right quadrant as shown. Let q = 5.0 pC.+gRWhat is the magnitude of the E-field at the center of the semicircle?Express your answer in N/C, to at least one digit after the decimal point.

Given: R = 4.0 cm = 0.04 m q=5.0 pc = 5*10-12 C

A glass rod forms a semicircle of radius R = 4.0 cm with a charge +q distributed uniformly along the left quadrant and -q distributed uniformly along the right quadrant as shown. Let q = 5.0 pC. +g What is the magnitude of the E-field at the center of the semicircle? Express your answer in N/C, to at least one digit after the decimal point.

A glass rod forms a semicircle of radius R = 4.0 cm with a charge +q distributed uniformly along the left quadrant and -q distributed uniformly along the right quadrant as shown. Let q = 5.0 pC. +g What is the magnitude of the E-field at the center of the semicircle? Express your answer in N/C, to at least one digit after the decimal point.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 8OQ: A circular ring of charge with radius b has total charge q uniformly distributed around it. What is...

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