Question
Asked Dec 25, 2019
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A granite ball of radius 2.00 m and emissivity 0.450 is heated to 135°C. (a) Convert the given temperature to Kelvin. (b) What is the surface area of the ball? (c) If the ambient temperature is 25.0°C, what net power does the ball radiate?

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Expert Answer

Step 1

(a)

The resistivity of the thermo pane window is,

Substitute the values,

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R= 2Rpane + Rurapped air = 2 k. pane k. trapped air 0.01m 0.01m 0.50 cm × 1.0cm x 1cm 1cm R= 2 0.84 W/m - °C 0.0234 W/m · °C 0.01m 0.005m 0.0234 W/m ·°C 0.84 W/m · °C = 0.44 m² . °C/W

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Step 2
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The rate of energy transfer through the window is, Q_ kA(T, – T,) kA(T, – T, ) Н Substitute the values, (1.0m² )(23°C – 0°C) Н: 0.44m² .°C/W = 52.3 W z 52 W

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