(a) How long (in s) will it take an 865 kg car with a useful power output of 38.0 hp (1 hpfrom rest.)= 746 W) to reach a speed of 13.0 m/s, neglecting friction? (Assume the car starts(b) How long (in s) will this acceleration take if the car also climbs a 2.80 m-high hill in the process?SAdditional MaterialsReading

Work energy theorem formula: W=change in kinetic energy =∆K =Kf-Ki =12mvf2-12mvi2…

(a) How long (in s) will it take an 865 kg car with a useful power output of 38.0 hp (1 hp = 746 W) to reach a speed of 13.0 m/s, neglecting friction? (Assume the car starts from rest.) (b) How long (in s) will this acceleration take if the car also climbs a 2.80 m-high hill in the process? Additional Materials O Reading

(a) How long (in s) will it take an 865 kg car with a useful power output of 38.0 hp (1 hp = 746 W) to reach a speed of 13.0 m/s, neglecting friction? (Assume the car starts from rest.) (b) How long (in s) will this acceleration take if the car also climbs a 2.80 m-high hill in the process? Additional Materials O Reading

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter7: Work And Kinetic Energy

Section: Chapter Questions

Problem 76P: Calculate the power output needed for a 950-kg car to climb a 2.00 slope at a constant 30.0 m/s...

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