A kindergarten class has seven left-handed children and fourteen right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed. (a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR) = P(RL) = P(LR) = P(LL) = (b) Find the probability distribution function for X. k 0 1 2 P(X = k)
A kindergarten class has seven left-handed children and fourteen right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed. (a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR) = P(RL) = P(LR) = P(LL) = (b) Find the probability distribution function for X. k 0 1 2 P(X = k)
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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A kindergarten class has seven left-handed children and fourteen right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed.
(a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.)
(b) Find theprobability distribution function for X.
P(RR) | = |
P(RL) | = |
P(LR) | = |
P(LL) | = |
(b) Find the
k | 0 | 1 | 2 |
---|---|---|---|
P(X = k) |
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