a landscape contractor is hired to cultivate ornamental plants in three new residential developments. the contractor charges the developer for each tree cultivated,an hourly rate to cultivate the ornamental plants, and a fixed delivery charge. in one development it took 211 labour hours to cultivate 244 ornamental plants for a cost of $9394. in a second development it took 128 labour hours to cultiv ate 283 ornamental plants for a cost of $8270. in the final development it took 165 labour hours to cultivate 386 ornamental plants for a cost of $10938. in total 504 labour hours were taken and 913 ornamental plants were cultivated. using cramer's rule of the inverse method, determine the cost for each tree, the hourly labour charge and the delivery charge.

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CR: Review Problem Set
Problem 37CR
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a landscape contractor is hired to cultivate ornamental plants in three new residential developments. the contractor charges the developer for each tree cultivated,an hourly rate to cultivate the ornamental plants, and a fixed delivery charge. in one development it took 211 labour hours to cultivate 244 ornamental plants for a cost of $9394. in a second development it took 128 labour hours to cultiv ate 283 ornamental plants for a cost of $8270. in the final development it took 165 labour hours to cultivate 386 ornamental plants for a cost of $10938. in total 504 labour hours were taken and 913 ornamental plants were cultivated. using cramer's rule of the inverse method, determine the cost for each tree, the hourly labour charge and the delivery charge.

Expert Solution
Step 1

Let rate per rose = $x1

Let rate per hour = $x2

let fixed rate = $x3

So according to question we have

244x1 + 211x2 +x3 = 9394

283x1 + 12x2 + x3 = 8270

386x1 + 165x2 + x3 = 10938

Let us use cramers rule her

X, Х Х3 b 1 244 | 211 1 9394 2 283 128 1 8270 3 386 | 165 1 10938

The determinant of the above matrix = 9992

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