A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a current of 385 A/phase. The total active power at the stator input terminals is 2344 kW, when operating at full load. The corresponding speed is accurately measured and found to be 709.2 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a) The power factor at full load b) The active power supplied to the rotor c) The total 17-R losses in the rotor

Power System Analysis and Design (MindTap Course List)
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ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
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Chapter11: Transient Stability
Section: Chapter Questions
Problem 11.1P
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2) A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a
current of 385 A/phase. The total active power at the stator input terminals is 2344 kW,
when operating at full load. The corresponding speed is accurately measured and found to
be 709.2 r/min. The stator is connected in wye and the resistance between two stator
terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses
are 12 kW. Calculate the following:
a) The power factor at full load
b) The active power supplied to the rotor
c) The total 12.R losses in the rotor
d) The load mechanical power (kW), torque (kN-m), and efficiency.
S = Va• V3- I
S= Vy 3•I
%3D
Transcribed Image Text:2) A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a current of 385 A/phase. The total active power at the stator input terminals is 2344 kW, when operating at full load. The corresponding speed is accurately measured and found to be 709.2 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: a) The power factor at full load b) The active power supplied to the rotor c) The total 12.R losses in the rotor d) The load mechanical power (kW), torque (kN-m), and efficiency. S = Va• V3- I S= Vy 3•I %3D
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