Question
Asked Sep 18, 2019
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A large bottle containing 883 g of water at 4 °C is removed from the refrigerator. How many kilojoules are absorbed to warm the water to room temperature of 22 °C?

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Expert Answer

Step 1

Given that,
Mass of water is 883 g.

The initial temperature is 4˚C.

The final temperature is 22˚C.

It is well known that the specific heat of water is 4.184 J/g˚C.

The amount of heat absorbed can be calculated by the use of heat equation given below:

Here,

Q is the amount of heat absorbed.

m is the mass of the substance.

ΔT is the change in temperature.

Change in temperature can be calculated as follows:

 

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Q =m x C x AT...1 AT Final temperature - Initial temperature =22°C - 4°C = 18°C

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Step 2

Substitute the given values in the equation (1) to calculate the amount of heat absorbed ...

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J Q 883 g x 4.184 g°C 18°C 66500.496 J

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