(a) Let n be a positive integer, and let t₁, ..., tn be positive numbers satisfying t₁+...+tn = 1. If I is an interval and f: IR is concave down, show that for any ₁,...,n in I, t₁x₁ + ...+ tnxn is in I, and f(t₁x₁ + + tnxn) ≥tif(x₁) + + tnf(xn). (b) The arithmetic mean geometric mean inequality says that if a₁, ..., an are n positive num- bers, then statements. a₁ + + an n > a₁...an. Use the concavity of a suitable function to prove this inequality. You need to justify all the
(a) Let n be a positive integer, and let t₁, ..., tn be positive numbers satisfying t₁+...+tn = 1. If I is an interval and f: IR is concave down, show that for any ₁,...,n in I, t₁x₁ + ...+ tnxn is in I, and f(t₁x₁ + + tnxn) ≥tif(x₁) + + tnf(xn). (b) The arithmetic mean geometric mean inequality says that if a₁, ..., an are n positive num- bers, then statements. a₁ + + an n > a₁...an. Use the concavity of a suitable function to prove this inequality. You need to justify all the
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.1: Postulates For The Integers (optional)
Problem 27E: Let x and y be in Z, not both zero, then x2+y2Z+.
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