A locust jumps at an angle of 55.0 degrees and lands 0.820 m from where it jumped. What is the maximum height of the locust during it’s jump? Ignore air resistance. If it jumps with the same initial speed at an angle of 45.0 degrees, what is the maximum height? If it jumps with the same initial speed at an angle of 45.0 degrees, what would the range be?

A locust jumps at an angle of 55.0 degrees and lands 0.820 m from where it jumped. What is the maximum height of the locust during it’s jump? Ignore air resistance. If it jumps with the same initial speed at an angle of 45.0 degrees, what is the maximum height? If it jumps with the same initial speed at an angle of 45.0 degrees, what would the range be?

Name: A locust jumps at an angle of 55.0 degrees and lands 0.820 m from wher
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: A locust jumps at an angle of 55.0 degrees and lands 0.820 m from where it jumped. What is the maximum height of the locust during it’s jump? Ignore air resistance. If it jumps with the same initial speed at an angle of 45.0 degrees, what is the maxi

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 9P

See similar textbooks

Similar questions

*Draw a simple diagram representation for the solution.In a game war, one team sets base on a cliff 15m high and 60m away from the opponent’s base. At what velocity must the attack be launched so that the lower base will be hit? The initial launch is at 20 degrees below the horizontal?
A machine launches a tennis ball at an angle of 25° above the horizontal at a speed of 14 meters per second and returns to level ground. Which combination of changes can produce an increase in the time of flight for the second launch? a. decrease the launch angle and decrease the ball's initial speed b. decrease the launch angle and increase the ball's initial speed c. increase the launch angle and decrease the ball's initial speed d. increase the launch angle and increase the ball's initial speed
A daredevil drove his motorcycle up an incline at 30 degree angle with the horizontal and got air borne at the end of the incline at 20 m/s, 11 m above the ground. How far horizontally did he land with his motorcycle on the ground, on a safety net?
A projectile is fired at 75 degrees above the horizontal line with an initial velocity v0. At which of the following angles the projectile will land at the same distance as it is landed when fired at 75 degrees? A. 15 degrees B. 25 degrees C. 35 degrees D. 45 degrees
In an article on the use of the sling as a weapon, the author states that a skilled slinger can sling a rock a distance of about 384 m. What is the minimum speed the rock must have when it leaves the sling to travel exactly 384 m? To solve this problem it will be necessary to first determine the required launch angle of the projectile. What launch angle must the projectile have in order to find the minimum speed required to achieve a given horizontal distance?
A stone is thrown horizontally from the highest point of a 95 m building and lands 115 m from the base of the building. Ignore air resistance, and use a coordinate system whose origin is at the highest point of the building, with positive y upwards and positive x in the direction of the throw. How long is the stone in the air in seconds? What must have been the initial horizontal component of the velocity, in meters per second? What is the vertical component of the velocity just before the stone hits the ground, in meters per second? What is the magnitude of the velocity of the stone just before it hits the ground, in meters per second?
A pilot flies horizontally at 1300 km/h, at height h = 35 m above initially level ground. However, at time t = 0, the pilot begins to fly over ground sloping upward at angle u = 4.3°. If the pilot does not change the airplane’s heading, at what time t does the plane strike the ground?
Consider a projectile launched form ground level at an angle of elevation with an initial velocity . The maximum horizontal range is given by xmax=(v 2/0 sin2θ)/g, where g is the acceleration due to gravity. Here is the problem: If a soccer ball is kicked from ground level with an initial velocity of 28 m/sec, what is the smallest positive angle at which the player should kick the ball to reach a teammate 48m down the field? Assume that the ball reaches the teammate at ground level on the fly. Round to the nearest tenth of a degree.
A cannon launches a cannonball from level ground with an initial speed of 80 m/s at an angle of 280 above the horizontal. What horizontal distance does the cannonball travel when the cannonball returns to the ground? Given the same initial velocity of launch, at what other angle above the ground can the cannonball be fired and achieve the same horizontal range as before? (Assume that g = 9.81 m/s2.) a. Range = 540 m, and angle = 420 above the horizontal b. Range = 600 m, and angle = 620 above the horizontal c. Range = 270 m, and angle = 620 above the horizontal d. Range = 540 m, and angle = 620 above the horizontal e. Range = 270 m, angle = 420 above the horizontal
a ball is launched with a velocity of magnitude 10.0 m/s, at an angle of 50.0° to the horizontal.The launch point is at the base of a ramp of horizontal length d1 6.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp. (a) Does the ball land on the ramp or the plateau? When it lands, what are the (b) magnitude and (c) angle of its displacement from the launch point?
In the figure, a ball is launched with a velocity of magnitude 7.00 m/s, at an angle of 41.0° to the horizontal. The launch point is at the base of a ramp of horizontal length d1 = 6.00 m and height d2 = 3.60 m. A plateau is located at the top of the ramp. Does the ball land on the ramp or the plateau? When it lands, what are the magnitude and angle of its displacement from the launch point?
A cannon ball is fired with an initial speed of 123 m/s at angle of 60 degrees from the horizontal. Express the initial velocity as a linear combination of its unit vector components. ( m/s) + ( m/s) At the maximum height, the speed of the cannon ball is v = ? m/s and the magnitude of its acceleration is a = ? m/s2. The time needed to reach maximum height is t = ? s. The maximum height reached by the cannon ball is H = ? m.