A long straight solenoid carries a current of 2.90 A and has 800 turns. The magnetic flux through each turn is 3.25 x 10-3 Weber (T-m2 or Wb). A voltmeter across the solenoid measures an induced voltage of 6.20 mV. Calculate the rate of change in the current flowing through the solenoid.

A long straight solenoid carries a current of 2.90 A and has 800 turns. The magnetic flux through each turn is 3.25 x 10-3 Weber (T-m2 or Wb). A voltmeter across the solenoid measures an induced voltage of 6.20 mV. Calculate the rate of change in the current flowing through the solenoid.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter31: Gauss’s Law For Magnetism And Ampère’s Law

Section: Chapter Questions

Problem 35PQ

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Concept explainers

Electromagnets

The word "electromagnet" is composed of two words, ‘electro’ and ‘magnet’. It is a type of magnet in which an electric current helps in the generation of a magnetic field. Electromagnets usually consist of two major parts, wire and a coil around which the wire is wound. This is called a solenoid. When an electric current is allowed to pass through the coiled wire, the electric current produces a magnetic field. This magnetic field is present only when current is passing through the wire.

Question

A long straight solenoid carries a current of 2.90 A and has 800 turns. The magnetic flux through each turn is 3.25 x 10^-3 Weber (T-m² or Wb). A voltmeter across the solenoid measures an induced voltage of 6.20 mV. Calculate the rate of change in the current flowing through the solenoid.

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