A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.16 m. The normal to the plane of the loop is parallel to a constant magnetic field (p=0") of magnitude 0.74 T. What is the change AD in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution? B (into paper) AD= 0.0296 Wb 4 I

icon
Related questions
Question
A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.16 m. The normal to
the plane of the loop is parallel to a constant magnetic field (p=0") of magnitude 0.74 T. What is the change AO in the magnetic flux
that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?
B (into paper)
AD=
Y
i 0.0296
Wb
V
Transcribed Image Text:A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.16 m. The normal to the plane of the loop is parallel to a constant magnetic field (p=0") of magnitude 0.74 T. What is the change AO in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution? B (into paper) AD= Y i 0.0296 Wb V
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer