This problem references the second type of application of Gauss’s law, locating charges on conductors.We may still be working on this a bit on Monday, and if so, either put this one off until then or viewthe video I posted on the topic.Two spherical, hollow conductors are concentrically nested as shown in the cross-sectional diagrambelow and electrically isolated from each other. A net charge of -3 nC is divided between theconductors, with a total of -12 nC on the inner conductor and +9 nC on the outer one. The charges are, of course, free to move between the surfaces within each shell but cannot move from one shell tothe other. The inner conductor has an inner radius of a=2 cm, outer radius of b=3 cm. The outerconductor has an inner radius of c=6 cm, an outer radius of d=8 cm. (a) In equilibrium, all of the excess charge is found on the surfaces. Why is there no charge betweena and b, nor between c and d?(b) Determine the net charge on each surface (ie how much charge is there at r = a, at r = b, at r= c and at r = d).(c) Is the charge on the outer surface equal to the net charge on the outer container, the net chargeof the system, or some other amount? Explain briefly.(d) Find the surface charge density at the outer surface (r = d.)(e) Find the electric field E(r) as a function of r from r=0 to r=10 cm. (Note that the functionalexpression may be different in different regions.) Plot the field as a function of r, using positivevalues if the field is outward and negative if inward.(f) Check that the charges you found in part b for the charge at r=a, b and c and the field youplotted in part e for the field between r=b and r=c are consistent with Gauss's law. Check alsothat the field just outside the outermost surface (at r just past 0.08 m) and the total chargeenclosed within that radius are consistent with Gauss's law.

This problem references the second type of application of Gauss’s law, locating charges on conductors. We may still be working on this a bit on Monday, and if so, either put this one off until then or view the video I posted on the topic. Two spherical, hollow conductors are concentrically nested as shown in the cross-sectional diagram below and electrically isolated from each other. A net charge of -3 nC is divided between the conductors, with a total of -12 nC on the inner conductor and +9 nC on the outer one. The charges are, of course, free to move between the surfaces within each shell but cannot move from one shell to the other. The inner conductor has an inner radius of a=2 cm, outer radius of b=3 cm. The outer conductor has an inner radius of c=6 cm, an outer radius of d=8 cm.

This problem references the second type of application of Gauss’s law, locating charges on conductors. We may still be working on this a bit on Monday, and if so, either put this one off until then or view the video I posted on the topic. Two spherical, hollow conductors are concentrically nested as shown in the cross-sectional diagram below and electrically isolated from each other. A net charge of -3 nC is divided between the conductors, with a total of -12 nC on the inner conductor and +9 nC on the outer one. The charges are, of course, free to move between the surfaces within each shell but cannot move from one shell to the other. The inner conductor has an inner radius of a=2 cm, outer radius of b=3 cm. The outer conductor has an inner radius of c=6 cm, an outer radius of d=8 cm.