A male black short furred cat mates with a ginger short furred female cat – without further information and using the information you have provided in your keys above, what are the possible genotypes of these two cats and why? (Hint: You need to show the genotypes as an expression of both genes together - and you need to explain the logic of how you have arrived at your answer). The pair of cats produce in their first litter together the following kittens: 3 tortoiseshell short fur females, 2 tortoiseshell long fur females, 3 ginger short fur males, and 1 ginger long fur male. From this information only (no genetic diagrams required), what evidence can you use to deduce the genetic identity of the parent cats?

A male black short furred cat mates with a ginger short furred female cat – without further information and using the information you have provided in your keys above, what are the possible genotypes of these two cats and why? (Hint: You need to show the genotypes as an expression of both genes together - and you need to explain the logic of how you have arrived at your answer). The pair of cats produce in their first litter together the following kittens: 3 tortoiseshell short fur females, 2 tortoiseshell long fur females, 3 ginger short fur males, and 1 ginger long fur male. From this information only (no genetic diagrams required), what evidence can you use to deduce the genetic identity of the parent cats?

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Description: A male black short furred cat mates with a ginger short furred female cat – without further information and using the information you have provided in your keys above, what are the possible genotypes of these two cats and why? (Hint: You need to show

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...

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A male black short furred cat mates with a ginger short furred female cat – without further information and using the information you have provided in your keys above, what are the possible genotypes of these two cats and why? (Hint: You need to show the genotypes as an expression of both genes together - and you need to explain the logic of how you have arrived at your answer).
A red-eyed female with a grey body is crossed with red-eyed male with a yellow body –without further information and using the information you have provided in your keys in partsB and D, what are the possible genotypes of these two flies and why?(Hint: You need to show the genotypes as an expression of both genes together -and you need to explain the logic of how you have arrived at your answer -NO genetic proofing / diagrams such as Punnet squares required at this stage)
Give typed explanation In pea plants, the tall allele (T) is dominant to the dwarf allele (t) and the yellow pea color allele (Y) is dominant to the green pea color allele (y). Cross TtYy with Ttyy. What would be the genotype and phenotype ratios in their offspring? (Please include the gametes produced by each parent.)
A pair of tail-less Manx cats mate. Phenotypes in progeny display a ratio of 1 long-tailed : 2 tail-less. Based on this information, which of the following statements is true? none of the statements listed here is true based on the given information onelgene codes for presence of the tail; long-tailed allele is dominant to tail-less allele two independently assorting genes code for presence of tail one gene codes for presence of the tail; tail-less allele is dominant to long-tailed allele two interactine genes code for presence of tail
As stated in Solved Problem 2, recessive mutation in certain mice called waltzers causes them to execute bizarre steps. W. H. Gates crossed waltzers with pure-breeding normal mice and found, among several hundred normal progeny, a single waltzing female mouse. This mouse was mated with a waltzing male, and her offspring were waltzers. When mated with a homozygous normal male, all her progeny were normal. Some of these normal males and females were intercrossed, and, unexpectedly, none of their progeny were waltzers. T. S. Painter examined the chromosomes of some of Gates’s waltzing mice that showed a breeding behavior similar to that of the original, unusual waltzing female. He found that these mice had the normal number of 40 chromosomes. In the unusual waltzers, however, one member of a chromosome pair was abnormally short. Interpret these observations as completely as possible, both genetically and cytologically.
In cats, black fur (B) is dominant over brown fur (b). Also, striped fur (A) is dominant over solid colored fur (a). What is the phenotype of a cat with the genotype Bbaa? What combinations of gametes could the Bbaa cat make? If the Bbaa cat mated with a cat that was heterozygous for both the color and pattern genes, what fraction of their kittens would be likely to have solid brown fur? Hint: draw your square on a separate paper to figure it out.
Phenotypically wild-type female Drosophila, whose mothers had spineless bristles (ss) and fathers had ebony bodies (e), produced the following offspring when crossed to homozygous males with ebony bodies and spineless bristles: 43 ebony bodies and spineless bristles 49 wild type 336 ebony bodies, wild type bristles 328 spineless bristles and wild type body color What is the map distance between the ebony body and spineless bristles loci?
Phenylketonuria (PKU) is an inherited disease caused by a recessive allele. Individuals with PKU have two recessive alleles and have very low levels of an enzyme that is needed to properly break down proteins. If a woman and her husband are both carriers and have three children, what is the probability of each of the following? Show your math. (Hint: You can represent your probabilities as fractions or decimals, but probabilities are always between 0 and 1) a. All three children are of normal phenotype. b. One or more of the three children have the disease. c.All three children have the disease.
One particularly useful feature of the Hardy-Weinberg equation is that it allows us to estimate the frequency of heterozygotes for recessive genetic diseases, assuming that Hardy-Weinberg equilibrium exists. As an example, let’s consider cystic fibrosis, which is a human genetic disease involving a gene that encodes a chloride transporter. Persons with this disorder have an irregularity in salt and water balance. One of the symptoms is thick mucus in the lungs that can contribute to repeated lung infections. In populations of Northern European descent, the frequency of affected individuals is approximately 1 in 2500. Because this is a recessive disorder, affected individuals are homozygotes. Assuming that the population is in Hardy-Weinberg equilibrium, what is the frequency of individuals who are heterozygous carriers?
A certain polled bull was bred to three cows. With cow A, which is polled, a horned calf was produced; with cow B, which is polled, a polled calf was produced; and with cow C, which is horned, a polled calf was produced. What are the genotypes of all these four animals [bull, cow A, cow B, and cow C], and what are the possible phenotypes and genotypes of the resulting offspring that you would expect from these three mating.
In guinea pigs, rough coat is dominant (R) to smooth coat (r), and black coat (B) is dominant to white coat 9. (b). A rough black guinea pig bred with a rough white one produces 29 rough black offspring, 31 rough white offspring, 11 smooth black offspring, and 9 smooth white offspring. Give the genotypes of the parents, the probability for the offspring, and the actual number of each kind of offspring you would expect. Genotype of the rough, black parent? Genotype of the rough, white parent? Genotypes Phenotypes What is the probability of getting rough, black offspring? What is the probability of getting rough, white offspring? What is the probability of getting smooth, black offspring? What is the probability of getting smooth, white offspring? Of the 80 offspring that were produced, we might have expected how many of them to be rough and black? Of the 80 offspring that were produced, we might have expected how many of them to be rough and white? Of the 80 offspring that were…
A recessive maternal effect mutant in zebrafish, called ichabod, results in embryos lacking heads that are non-viable. You have been instructed to identify females that are homozygous for the ichabod mutant allele. At your disposal are a tank of wild-type fish (males and females), a tank of male and female parental fish that are all heterozygous for the ichabod mutant allele (ichabod/+), and a tank of F1 fish derived from a cross between a heterozygous male and heterozygous female (ichabod/+). Which of the following would be a way to identify females that are homozygous mutant, i.e. ichabod/ichabod? Select all answers that would work.