A man returning from ice fishing trip pulls a sled with fish. Total mass of the sled and  fish is 50.0 kg. (b) Suppose the coefficient of kinetic friction between sled and snow is 0.20. The man pulls the sled 5.0 m by exerting a force of 120 N at 0°. Find the work done by force of frictional.

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A: Given, Pushing force , F = 7887.04 N Distance, s = 26.62 m Coefficient of kinetic friction, μk =…

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A: Given Data : Mass of luggage, m= 10 Kg                      Force= 20N                      Vertical…

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A: 7) work done by the friction = final kinetic energy - initial potential energy W = (1/2)(10)(2)2 -…

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A: Given, Mass of block m = 3.57 Kg Distance d = 4.06 m Force F = 7.68 N  Angle θ=15∘

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A: When the object moves in a pure rolling motion, the work done by the friction will be zero.

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A: W=Fdcosθ=70 N3 mcos15°=204 J

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Q: Spiderman, whose mass is 80.0 kg, is dangling on the free end of a 12.0-m-long rope, the other end…

A: Mas, m = 80 kg  Length of rope, l = 12 m

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A: Calculate the power generated. P=F→·v→=17 Nx^+12 Ny^·5.1 m/sx^=17 N5.1 N m/s+12 N0=86.1 N·m/s×1 J1…

Q: (1.1) A horizontal force pulls a mass of 2,25 kg a distance of 8 m across a rough horizontal surface…

A: Solution:

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Q: how much work is done on a cart by a force F=(10i+5j)kN that causes a displacement of d=(2i+0j)m?

A: The work done is given by  W =  F→ . d→ where, F is the force vector and d is the displacement…