A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4 years, and standard deviation of 1.2 years. If you randomly purchase one item, what is the probability it will last longer than 4 years?

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.7…

A: It was given that a manufacturer knows that their items have a normally distributed lifespan. The…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 14.2…

A: GivenMean(μ)=14.2standard deviation(σ)=2.2

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.9…

A: Given that, Mean = 5.9 Standard deviation = 1.8

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 10.5…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.3…

A: Given that A manufacturer knows that their items have a normally distributed lifespan, with a mean…

Q: A manufacturer knows that their items have a lengths that are approximately normally distributed,…

A:

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 10 inches,…

A: We have given that, Items are normally distributed with Mean(Mu) = 10 inches and standard deviation…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.2…

A: Given: The mean lifespan of the items is μ=12.2 years. The standard deviation is σ=2.5 years. Let Y…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.2…

A: We have given that, Normally distributed with mean = 12.2 . And Standard deviation = 1.9 . We have…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.9…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.7…

A: According to provided data, the mean is equal to 14.7 years The standard deviation is equal to 1.6…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 13.5…

A: Let "X" be the length of the items.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.2…

A: Let X be the time that an item will last long

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 7.4 inches,…

A: Let "M" be the mean length of the item in inches.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.8…

A: The mean is 11.8 and the standard deviation is 2.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 13.2…

A: As per guideline expert have to answer first question only since i have done all for you...

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.1…

A: Here the life span of the item follows Normal distribution with mean=14.1 and standard deviation=4.5

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 2.6…

A: Central Limit Theorem for mean: If a random sample of size n is taken from a population having mean…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 10.1…

A: Given: μ=10.1σ=3.1

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 18.8…

A: The probability that it is less than 18.8 inches long when one item chosen at random is obtained…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.3…

A: Given:     = 7.3 , = 1.8   To find the probability, we need to find Z scores first.…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 19.3 inches…

A: It is given that the mean is 19.3 and the standard deviation is 2.

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.9…

A: The probability that it will last longer than 11 years is obtained below: From the given…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.5…

A:

Q: The life span of a particular species of turtle is normally distributed with a mean of 180 years and…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 6.4…

A: The mean and standard deviation can be calculated as: n= 22

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.3…

A: Let x be the lifespan which follows normal distribution with mean 7.3 and standard deviation 0.7.…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.2…

A: Let X is the normally distributed lifespan of an item. μ=11.2,σ=2.5

Q: manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.5 years,…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.2…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 6 years,…

A: Mean = 6 Standard deviation = 1.8 Sample size = 4

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 4.5…

A: GivenMean(μ)=4.5standard deviation(σ)=1.5

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.4…

A: Let us consider X be a random variable which is used to denote the lifespan of the item. It is given…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.9…

A: Let X be the random variable from normal distribution with mean (μ) = 3.9 and standard deviation (σ)…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.5…

A: It is given that the items are normally distributed life span with mean 14.5 years and standard…

Q: anufacturer knows that their items have a normally distributed lifespan, with a mean of 10.5 years,…

A: Given data,Mean μ=10.5sd    σ=3.2P(X>4)=?

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 11.7…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.3…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.3…

A: Given Information: Mean μ=12.3 years Standard deviation σ=0.8 years.   If you randomly purchase 3…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 5 inches,…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 11.9…

A:

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 20 inches,…

A: Determine the Z score for the random variable X equals 23.1., The Z score for the random variable X…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3 years,…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 14.7…

A: Given that, Mean, μ=14.7Standard Deviation, σ=4.8 The standard deviation for the 7 items is,…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 9.6…

A: Let X denote the  items lifespan and it follows normal distribution with a mean of μ=9.6 years, and…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 17 inches,…

A: Let X be the length of the item. We have, μ=17, σ=5.4  We want to find out P(X<4.8) when X=4.8,…

Q: A manufacturer knows that their items have a normally distributed length, with a mean of 10 inches,…

A: Mean = 10 Standard deviation = 3.2

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.7…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.1…

A:

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.1…

A: The items are normally distributed with mean 12.1 and variance 1.1 μ=12.1σ=1.1