A Martian day is 24.66 hours long. A satellite is in a circular orbit about Mars. The orbit is in the plane containing Mar's equator. At what orbital radius will the satellite be in geosynchronous orbit and thereby remain directly above the same point on the equator? (MMars 6.39 x 1023 kg G 6.67 x 1011 N m²kg? ) O 42,250 km O 22,500 km O 36,500 km O 20,400 km

A Martian day is 24.66 hours long. A satellite is in a circular orbit about Mars. The orbit is in the plane containing Mar's equator. At what orbital radius will the satellite be in geosynchronous orbit and thereby remain directly above the same point on the equator? (MMars 6.39 x 1023 kg G 6.67 x 1011 N m²kg? ) O 42,250 km O 22,500 km O 36,500 km O 20,400 km

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter13: Gravitation

Section: Chapter Questions

Problem 13.9CYU: Check Your Understanding The nearly circular orbit of Saturn has an average radius of about 9.5 AU...

See similar textbooks

Similar questions

After Cares was promoted to a dwarf planet, we now recognize the largest known asteroid to be Vesta, with a mass of 2.671020kg and a diameter ranging from 578 km to 458 km. Assuming that Vesta is spherical with radius 520 km, find the approximate escape velocity from its surface.
Check Your Understanding The nearly circular orbit of Saturn has an average radius of about 9.5 AU and has a period of 30 years, whereas Uranus averages about 19 AU and has a period of 84 years. Is this consistent with our results for Halley’s comet?
If a spacecraft is headed for the outer solar system, it may require several gravitational slingshots with planets in the inner solar system. If a spacecraft undergoes a head-on slingshot with Venus as in Example 11.6, find the spacecrafts change in speed vS. Hint: Venuss orbital period is 1.94 107 s, and its average distance from the Sun is 1.08 1011 m.
A planet has two moons of equal mass. Moon 1 is in a circular orbit of radius r. Moon 2 is in a circular orbit of radius 2r. What is the magnitude of the gravitational force exerted by the planet on Moon 2? (a) four times as large as that on Moon 1 (b) twice as large as that on Moon 1 (c) equal to that on Moon 1 (d) half as large as that on Moon 1 (e) one-fourth as large as that on Moon 1
It was stated that a satellite with negative total energy is in a bound orbit, whereas one with zero or positive total energy is in an unbounded orbit. Why zero or positive total energy is in an unbounded orbit. Why is this true? What choice for gravitational potential energy was made such that this is true?
What is the gravitational potential energy of Saturn due to the Sun? Assume MSaturn = 5.68×1026 kg, MSun = 2.0×1030 kg, and the orbital distance is r= 1.43×109 km.
The escape speed from a distant planet is 39 km/s. If the acceleration of gravity on the planet surface is 11.5 m/s2, what is the radius of the planet?
A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite staysover a fixed point on the equator). Use Kepler’s Third Law to showthat in a circular geosynchronous orbit, the distance from the center ofthe earth is R ≈ 42,246 km. Then compute the altitude h of the orbitabove the earth’s surface. The earth has mass M ≈ 5.974 × 1024 kgand radius R ≈ 6371 km.
A minimum-energy transfer orbit to an outer planet consists of putting a spacecraft on an elliptical trajectory with the departure planet corresponding to the perihelion of the ellipse, or the closest point to the Sun, and the arrival planet at the aphelion, or the farthest point from the Sun. (Assume the orbital radius of the Earth is 1.50 1011 m, and the orbital radius of Mars is 2.28 1011 m.) (a) Use Kepler's third law to calculate how long it would take to go from Earth to Mars on such an orbit as shown in the figure above. yr(b) Can such an orbit be undertaken at any time? Yes or No Explain.
A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite stays over a fixed point on the equator). Use Kepler’s Third Law to show that in a circular geosynchronous orbit, the distance from the center ofthe earth is R ≈ 42,246 km. Then compute the altitude h of the orbit above the earth’s surface. The earth has mass M ≈ 5.974 × 10^(24) kg and radius R ≈ 6371 km.
At what altitude above Earth's surface would the gravitational acceleration be 3.80 m/s2? (Take the Earth's radius as 6370 km.)
An object of mass mm is launched from a planet of mass MM and radius RR. a) Derive and enter an expression for the minimum launch speed needed for the object to escape gravity, i.e. to be able to just reach r=∞. b) Calculate this minimum launch speed (called the escape speed), in meters per second, for a planet of mass M=2.73×1023kg and R=86.2×103km.