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A mechanic's pay is $10.00 per hour for regular time and time-and-a-half for overtime. The weekly wage function is [10h, 0 40 W(h) = where h is the number of hours worked in a week. (a) Evaluate W(30), W(40), W(45), and W(50). W(30) W(40) W(45) W(50) - $ (b) The company decreases the regular work week to 38 hours. What is the new weekly wage function? 0

A mechanic's pay is $10.00 per hour for regular time and time-and-a-half for overtime. The weekly wage function is [10h, 0 40 W(h) = where h is the number of hours worked in a week. (a) Evaluate W(30), W(40), W(45), and W(50). W(30) W(40) W(45) W(50) - $ (b) The company decreases the regular work week to 38 hours. What is the new weekly wage function? 0

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Functions
Section9.1: Relations And Functions
Problem 75PS
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A mechanic's pay is $10.00 per hour for regular time and time-and-a-half for overtime. The weekly wage function is 0 <hs 40 - 40) + 400, h> 40 where h is the number of hours worked in a week. Wh) - (10h, (a) Evaluate W(30), W(40), W(45), and W(50). W(30) -$ W(40) W(45) W(50) - $ (b) The company decreases the regular work week to 38 hours. What is the new weekly wage function? 0 <hs W(h) - (c) The company increases the mechanic's pay to $12.00 per hour. What is the new weekly wage function? Use a regular work week of 40 hours. 0 <hs W(h)- h>
Transcribed Image Text:A mechanic's pay is $10.00 per hour for regular time and time-and-a-half for overtime. The weekly wage function is 0 <hs 40 - 40) + 400, h> 40 where h is the number of hours worked in a week. Wh) - (10h, (a) Evaluate W(30), W(40), W(45), and W(50). W(30) -$ W(40) W(45) W(50) - $ (b) The company decreases the regular work week to 38 hours. What is the new weekly wage function? 0 <hs W(h) - (c) The company increases the mechanic's pay to $12.00 per hour. What is the new weekly wage function? Use a regular work week of 40 hours. 0 <hs W(h)- h>
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