A mixture of 0.03430 mol of C₂H6, 0.04797 mol of N₂, 0.01967 mol of NH3, and 0.02946 mol of C₂H4 is placed in a 1.0-L steel pressure vessel at 1257 K. The following equilibrium is established: 3 C₂Hg(9) + 1 N₂(g) = 2 NH₂(g) + 3 C₂H4(9) At equilibrium 0.003643 mol of NH3 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H, N₂, NH3, and C₂Ha Peq(C₂H6)= Peg (N₂) = Peq(NH3)= Peg(C₂H4) (b) Calculate Kp for this reaction. Kp

Chemistry: The Molecular Science
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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
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A mixture of 0.03430 mol of C₂H6, 0.04797 mol of N₂, 0.01967 mol of NH3, and 0.02946 mol of C₂H4 is placed in a 1.0-L steel
pressure vessel at 1257 K. The following equilibrium is established:
3 C₂Hg(9) + 1 N₂(g) 2 NH₂(g) + 3 C₂H4(9)
At equilibrium 0.003643 mol of NH3 is found in the reaction mixture.
(a) Calculate the equilibrium partial pressures of C₂H, N₂, NH3, and C₂H4.
Peq(C₂H6)=
Peg (N₂) =
Peq(NH3)=
Peg(C₂H4)
(b) Calculate Kp for this reaction.
Kp
Transcribed Image Text:A mixture of 0.03430 mol of C₂H6, 0.04797 mol of N₂, 0.01967 mol of NH3, and 0.02946 mol of C₂H4 is placed in a 1.0-L steel pressure vessel at 1257 K. The following equilibrium is established: 3 C₂Hg(9) + 1 N₂(g) 2 NH₂(g) + 3 C₂H4(9) At equilibrium 0.003643 mol of NH3 is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of C₂H, N₂, NH3, and C₂H4. Peq(C₂H6)= Peg (N₂) = Peq(NH3)= Peg(C₂H4) (b) Calculate Kp for this reaction. Kp
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