A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established: 2 NO + 2 H₂(g) = N2(g) + 2 H₂O(g) At equilibrium [NO] = 0.030 M. The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0. Calculate the equilibrium concentrations (in M) of: More Information X H₂(g) XN₂ (g) X H₂O (g) Question Answer Your answer -.020 is Your answer .035 is in Your answer .170 is i Tol: 0.0001 Tol: 0.001 Tol: ±0.001
A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established: 2 NO + 2 H₂(g) = N2(g) + 2 H₂O(g) At equilibrium [NO] = 0.030 M. The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0. Calculate the equilibrium concentrations (in M) of: More Information X H₂(g) XN₂ (g) X H₂O (g) Question Answer Your answer -.020 is Your answer .035 is in Your answer .170 is i Tol: 0.0001 Tol: 0.001 Tol: ±0.001
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.41PAE: Because calcium carbonate is a sink for CO32- in a lake, the student in Exercise 12.39 decides to go...
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