Question
Asked Nov 18, 2019
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A mixture of argon and nitrogen gases, at a total pressure of 965 mm Hg, contains 7.40 grams of argon and 7.47 grams of nitrogen. What is the partial pressure of each gas in the mixture?

PAr =  __mm Hg
PN2 = __ mm Hg

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Expert Answer

Step 1

According to the Dalton’s law of partial pressures, in a given mixture containing non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures which is exerted by the individual gases in the mixture.

Step 2

The partial pressure of a given as is equal to the product of the mole fraction of the gas and the total pressure exerted by the gases present in the mixture.

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A otal P, is the partisl pressure of gas A X is the mole fraction of the gas A Pris the total pressure of the given mixture tota

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Step 3

The mass of Argon gas is given to be 7.40 g.

The mass of Nitrogen gas is given to be 7.47 g...

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Mass Number of moles of Argon= Molar mass 7.40 g 39.94 g/mol 0.185 mol 7.47 g Number of moles of Nitrogen=- 28.01 g/mol 0.266 mol

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