A mixture of three gasses contains 5 total moles and has a total pressure of 3.2 atm. If there are 1.8 moles of He, 0.95 moles of Ne, what is the partial pressure of the third gas, kr?

Chemistry: Principles and Practice
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ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter6: The Gaseous State
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Problem 6.85QE
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A mixture of three gasses contains 5 total moles and has a total pressure of 3.2 atm. If there are 1.8 moles of He, 0.95 moles of Ne, what is the partial pressure of the third gas, kr?
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Step 1

Recall the following relations to calculate partial pressure

                   partial pressure=mole fraction×total pressureHere, 1.8 moles of He,0.95 moles of Ne are present along with Kr making total mole=5Again, XHe + XNe + Xkr=1

Here, XHe is mole fraction of He         XNe is mole fraction of Ne         XKr is mole fraction of KrGiven that total pressure of the mixture is 3.2 atm

 

 

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